2u^2-5u-1=0

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Solution for 2u^2-5u-1=0 equation: 



2u^2-5u-1=0

a = 2; b = -5; c = -1;
Δ = b2-4ac
Δ = -52-4·2·(-1)
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{33}}{2*2}=\frac{5-\sqrt{33}}{4}
$


$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{33}}{2*2}=\frac{5+\sqrt{33}}{4}
$

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